Forum Discussion
Extract String
Extract String
Hi All,
My input string is BC89RACJ0098457632.
I've to extract the string and to store as like
A=BC
B=89
C=RACJ
D=0098457623
and i've to check, whether A & C is a string and B & D as an integer ?
give some ideas to do this..
Thanks & Regards,
2 Replies
hope this might help...
StrObject is an Array of string defined at global level
str is a string initially "BC89RACJ0098457632";
resultstr is some fixed array of string. resultAlpha is some fixed array of string.FinalResultStringArr is some array of string.
FinalResultNumberArr is some fixed array of integer. regexAlphabet is some RegularExpression; regexAlphabet = regularExpression("[0-9]");regexNumber is some RegularExpression;
regexNumber = regularExpression("[A-Z]");resultstr = regexAlphabet.split(str);
resultAlpha = regexNumber.split(str);for each string in resultstr do
{ print(it); StrObject.append(it); } for each string in resultAlpha do { print(it); }Hi,
You can use Blaze built-in functtion portable().subString() to achieve this.
mainStr = "BC89RACJ0098457632".
a = portable().subString(mainStr, 1,2).
In this case 'a' will have the value as BC
Similarly the values in b,c,d can be achieved as follows:-
b = portable().subString(mainStr,3,4).
c = portable().subString(mainStr,5,8).
d = portable().subString(mainStr,9,18).
